How do you solve #2x^2-9x-35=0#?

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Answer 1 · 2016-09-01T02:43:29

#x = -5/2 and 7#

Solve by factoring.

#2x^2 - 9x - 35 = 0#

Find two numbers that multiply to #2 xx -35 = -70# and that add to #-9#. Two numbers that do this are #-14 and 5#.

#2x^2 - 14x + 5x - 35 = 0#

#2x(x - 7) + 5(x - 7) = 0#

#(2x + 5)(x - 7) = 0#

#x = -5/2 and 7#

Hopefully this helps!