How do you solve $2x^2 + 8x - 3 = 0$ using the quadratic formula?

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Answer 1 · 2016-08-06T07:53:40

$x=2-sqrt22/2$ or $x=2+sqrt22/2$

Quadratic formula gives the solution of quadratic equation $ax^2+bx+c=0$ as $x=(-b+-sqrt(b^2-4ac))/(2a)$ .

Hence solution of $2x^2+8x-3=0$ using the formula is given by

$x=(-8+-sqrt(8^2-4xx2xx(-3)))/(2xx2)$ or

$x=(-8+-sqrt(64+24))/4$ or

$x=(-8+-sqrt88)/4$ or

$x=-2+-sqrt(4xx22)/4=2+-2/4sqrt22$ or

$x=2+-sqrt22/2$ i.e.

$x=2-sqrt22/2$ or $x=2+sqrt22/2$

How do you solve 2x^2 + 8x - 3 = 02x^2 + 8x - 3 = 0 using the quadratic formula?