How do you solve $-2x^2-7x=-1.5$ using the quadratic formula?

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How do you solve $-2x^2-7x=-1.5$ using the quadratic formula?

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Answer 1 · 2017-08-25T09:38:04

$x~~ -3.7,x~~ 0.2$

Explanation:

$"rearrange and equate to zero"$

$rArr-2x^2-7x+1.5=0$

$"with "a=-2,b=-7,c=1.5$

$"solving using the "color(blue)"quadratic formula"$

$"for the quadratic "ax^2+bx+c=0$

$•color(white)(x)x=(-b+-sqrt(b^2-4ac))/(2a)$

$rArrx=(7+-sqrt(49+12))/(-4)$

$rArrx=(7+sqrt61)/(-4)" or "x=(7-sqrt61)/(-4)$

$rArrx~~ -3.7" to 1 dec. place or "x~~ 0.2" to 1 dec. place"$

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How do you solve $-2x^2-7x=-1.5$ using the quadratic formula?

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How do you solve $-2x^2-7x=-1.5$ using the quadratic formula?