How do you solve $2x^2+6x+4=0$ using the quadratic formula?

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Answer 1 · 2015-08-10T07:27:52

The solutions for the equation are:
$color(blue)(x=-1 , x=-2$

$2x^2+6x+4=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=2, b=6, c=4$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (6)^2-(4*(2)*4)$

$= 36 -32 = 4$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-6)+-sqrt(4))/(2*2) = ((-6+-2))/4$

$x = ((-6+2))/4 = -4/4 = -1$

$x = ((-6-2))/4 = -8/4 = -2$

$color(blue)(x=-1 , x=-2$

How do you solve 2x^2+6x+4=02x^2+6x+4=0 using the quadratic formula?