How do you solve 2x^2=6x-2 using the quadratic formula?

1 Answer
Shwetank Mauria
Feb 20, 2016

x=(3+sqrt(5))/2 or (3-sqrt(5))/2

Explanation:

Using quadratic formula, solution of the equation ax^2+bx+c=0 is given by x=(-b+-sqrt(b^2-4ac))/(2a). Note that the quadratic equation is in its general form.

Hence converting the equation to its general form, the equation 2x^2=6x−2 this becomes 2x^2-6x+2=0 or dividing by 2, x^2-3x+1=0 and as such a=1, b=-3 and c=1.

Hence, solution is given by x=(-(-3)+-sqrt((-3)^2-4*1*1))/(2*1) or

x=(3+-sqrt(9-4))/2 or x=(3+-sqrt(5))/2 i.e.

x=(3+sqrt(5))/2 or (3-sqrt(5))/2

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