How do you solve 2x^2 + 5x + 5 = 0 using the quadratic formula?

1 Answer
Waleed A.
Oct 15, 2015

x = (-5 + 3.87i) / 4, x = (-5 -3.87i) / 4

Explanation:

Standard Quadratic Equation:
ax^2 + bx + c = 0

Where,
a is the constant with x to the power 2.
b is the constant with x to the power 1.
c is the constant.

Standard Quadratic Formula:

x = (-b+-sqrt(b^2 - 4(a)(c))) / (2(a))

Given Equation:

2x^2 + 5x + 5 = 0

Here,

a = 2
b = 5
c = 5

x = (-5 +- sqrt((5)^2 - 4(2)(5))) / (2(2))
x = (-5 +- sqrt(25 - 40)) / 4
x = (-5 +- sqrt(-15)) / 4
x = (-5 +- 3.87i) / 4
x = (-5 + 3.87i) / 4, x = (-5 -3.87i) / 4

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