How do you solve $2x^2+5x= - 4$ using the quadratic formula?

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Answer 1 · 2016-02-19T20:39:48

( $-b + or -$ $sqrt($ b^2 -4(a)(C)))÷(#2a) quadratic formula must equal zero

x

− $b^2$ ±√b−4ac

2a

move 4 to the other side so

$2x^2 + 5x + 4=0$

$2x^2=a$
$5x=b$
$4=c$