How do you solve #2x^2+5=41#?
1 Answer
May 15, 2018
Explanation:
#"isolate "2x^2" by subtracting 5 from both sides"#
#rArr2x^2=41-5=36#
#"divide both sides by 2"#
#rArrx^2=36/2=18#
#color(blue)"take the square root of both sides"#
#sqrt(x^2)=+-sqrt18larrcolor(blue)"note plus or minus"#
#rArrx=+-sqrt18=+-3sqrt2#
