How do you solve 2x^2-3x-2=0 using the quadratic formula?

1 Answer
Nghi N.
Apr 10, 2016

2 and - 1/2

Explanation:

Use the improved quadratic formula, also called the quadratic formula in intercept form (Google, Yahoo, Bing Search)
y = 2x^2 - 3x - 2 = 0
D = d^2 = b^2 - 4ac = 9 + 16 = 25 ---> d = +- 5
There are 2 real roots:
x = -b/(2a) +- d/(2a) = 3/4 +- 5/4
x1 = 8/4 = 2
x2 = -2/4 = - 1/2

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