How do you solve $2x^2 = 14x + 20$ using the quadratic formula?

Question

2043 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-23T10:10:34

$x_1=-1,22$
$x_2=8,22$

$2x^2=14x+20$
$2x^2-14x-20=0$
$2(x^2-7x-10)=0$
$x^2-7x-10=0$

$ax^2+bx+c=0$
$a=1" ; "b=-7" ; "c=-10$

$Delta=sqrt(b^2-4*a*c)$

$Delta=sqrt(49+4*1*10)$

$Delta=sqrt89$

$Delta=9,43$

$x_1=(-b-Delta)/(2*a)$

$x_1=(7-9,43)/2$

$x_1=-1,22$

$x_2=(-b+Delta)/(2*a)$

$x_2=(7+9,43)/2$

$x_2=8,22$

How do you solve 2x^2 = 14x + 202x^2 = 14x + 20 using the quadratic formula?