How do you solve #2x^2-13x-7=0#?

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Answer 1 · 2016-06-04T03:40:49

#x = -1/2 or x= 7#

The trinomial #2x^2-13x-7=0# can be factored

#(2x +1)(x-7)=0#

Now set each factor equal to zero

#2x+1=0#

#2xcancel(+1)cancel(-1)=0-1#

#2x=-1#

#(cancel(2)x)/cancel2=-1/2#

#x=-1/2#

and #x-7=0#

#xcancel(-7)cancel(+7)= 0+7#

#x = 7#