How do you solve $2x^2 - 10x + 7 = 0$ ?

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Answer 1 · 2015-08-15T12:29:40

The solutions are:
$color(blue)(x=(5+sqrt(11))/2$

$color(blue)(x=(5-sqrt(11))/2$

$2x^2−10x+7=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=2, b=-10, c=7$

The Discriminant is given by:

$color(blue)(Delta=b^2-4*a*c$

$= (-10)^2-(4* 2 * 7)$

$= 100 -56=44$

The solutions are found using the formula
$color(blue)(x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-10)+-sqrt(44))/(2*2) = (10+-2sqrt(11))/4$

$x=(cancel2( 5+-sqrt(11)))/cancel4$

$color(blue)(x=(5+sqrt(11))/2$

$color(blue)(x=(5-sqrt(11))/2$

How do you solve 2x^2 - 10x + 7 = 02x^2 - 10x + 7 = 0?