How do you solve $2x^2 + 10x + 12 = 0$ using the quadratic formula?

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Answer 1 · 2016-03-15T19:41:50

$x_1=-3$
$x_2=-2$

$2x^2+10x+12=0$
$ax^2+bx+c=0$

$x_"1,2"=(-b±sqrt(b^2-4*a*c))/(2*a)$

$x_1=(-10-sqrt(100-4*2*12))/(2*2)$
$x_1=(-10-sqrt4)/4$
$x_1=(-10-2)/4$
$x_1=-12/4" "x_1=-3$

$x_2=(-10+sqrt(100-4*2*12))/(2*2)$
$x_2=(-10+2)/4$

$x_2=-8/4$
$x_2=-2$

How do you solve 2x^2 + 10x + 12 = 02x^2 + 10x + 12 = 0 using the quadratic formula?