How do you solve #2sqrt(a-1)=4sqrt(a)#?

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Answer 1 · 2015-05-19T04:47:12

#sqrt(a - 1) #= #2sqrta#
Square both side:
(a - 1) = 4a -> 3a = -1 -> a = -1/3
a can't be negative, then solving is impossible.