How do you solve $2sinx+sqrt3=0$ and find all solutions in the interval $0<=x<360$ ?

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Answer 1 · 2016-12-05T10:59:00

The answer is $S={240º,300º}$

We rewrite the equation

$sinx=-sqrt3/2$

$sin60º=sqrt3/2$

So, the answers lie in the 3rd and 4th quadrant

So, $x=240$ º and $x=300$ º

How do you solve 2sinx+sqrt3=02sinx+sqrt3=0 and find all solutions in the interval 0<=x<3600<=x<360?