How do you solve $2sinx cosx-sqrt3 cosx=0$ ?

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How do you solve $2sinx cosx-sqrt3 cosx=0$ ?

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Answer 1 · 2016-05-14T05:05:09

$pi/2, (3pi)/2, pi/3 and (2pi)/3$ for $(0, 2pi)$

Explanation:

$2sin x.cos x - sqrt3cos x = 0$
$cos x(2sin x - sqrt3) = 0$
Trig table and unit circle -->
a. cos x = 0 --> $x = pi/2$ and $x = (3pi)/2$
b. $sin x = sqrt3/2$ --> $x = pi/3$ and $x = (pi - pi/3) = (2pi)/3$

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How do you solve $2sinx cosx-sqrt3 cosx=0$ ?

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