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How do you solve #2sinx^2=1#?

1 Answer

Sep 19, 2016

#x = (pi) / (4)#

Explanation:

We have: #2 sin(x)^(2) = 1#

#=> 2 sin^(2)(x) = 1#

#=> sin^(2)(x) = (1) / (2)#

#=> sin(x) = sqrt((1) / (2))#

#=> sin(x) = (sqrt(2)) / (2)#

#=> x = arcsin((sqrt(2)) / (2))#

#=> x = (pi) / (4)#

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