How do you solve $(2sintheta-1)^4=0$ ?

1 Answer

Aug 31, 2016

$θ = pi/6 + 2kpi$ or $θ = 5/6pi + 2kpi$ , $k in Z$

Explanation:

if $(2sinθ−1)^4=0$
then $2sinθ−1 = 0$
thus $sinθ = 1/2$
elementary solution $θ_0$ = $pi/6$
adding period
$θ = pi/6 + 2kpi$ or $θ = 5/6pi + 2kpi$ , $k in Z$

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How do you solve $(2sintheta-1)^4=0$ ?

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