How do you solve $2 sin 2 x + \sqrt{3} = 0$ $2sin2x+sqrt3=0$ for $0 \leq x \leq 360$ $0<=x<=360$ ?

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Answer 1 · 2016-11-12T13:05:45

$x=120° or x=150° or x=300° or x=330°$

$sin2x=-sqrt3/2$

$2x=240° or 2x=300° or 2x=600° or 2x=660°$

then

$x=120° or x=150° or x=300° or x=330°$

How do you solve 2sin2x+sqrt3=02sin2x+√3=02sin2x+sqrt3=0 for 0<=x<=3600≤x≤3600<=x<=360?