How do you solve $2sin^2theta=1$ ?

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How do you solve $2sin^2theta=1$ ?

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Answer 1 · 2016-11-20T21:06:02

$theta=((2k+1))/4pi , k in mathbbZ$

Explanation:

$2sin^2theta=1$
$sin^2 theta=1/2$
$sintheta=sqrt (1/2) or sintheta=-sqrt(1/2)$
$sintheta=sqrt2/2 or sintheta=-sqrt2/2$
$theta=pi/4+2kpi or theta=pi-pi/4+2kpi or theta=-pi/4+2kpi or theta=-(pi-pi/4)+2kpi, k in mathbbZ$
$theta=pi/4+kpi or theta=-pi/4+kpi, k in mathbbZ$
$theta=pi/4+kpi/2, k in mathbbZ$
or written a bit differently
$theta=((2k+1))/4pi , k in mathbbZ$

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How do you solve $2sin^2theta=1$ ?

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