How do you solve $2secxtanx+2secx+tanx+1=0$ in the interval [0,360]?

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Answer 1 · 2016-09-08T13:38:17

The solution set is ${(3pi)/4, (7pi)/4}$ .

Factor:

$2secx(tanx + 1) + 1(tanx + 1) = 0$

$(2secx + 1)(tanx + 1)= 0$

$secx = -1/2 and tanx = -1$

$cosx = -2 and tanx = -1$

$x = O/ and x = (3pi)/4 and (7pi)/4$

Hence, the solution set is ${(3pi)/4, (7pi)/4}$ .

Hopefully this helps!

How do you solve 2secxtanx+2secx+tanx+1=02secxtanx+2secx+tanx+1=0 in the interval [0,360]?