How do you solve 2m^2+10=210?

1 Answer
Kayla
Jul 23, 2016

color(purple)("m = 10

Explanation:

color(magenta)("Subtract 10 on both sides of the equation:"
2m^(2)+cancel10=210
color(white)(aaaa) cancel-10 -10

On the left side you should be left with 2m^(2), and on the right side you are left with 200:

2m^(2)= 200

Next, divide both sides both 2 in order to get the variable and constant on opposite sides of the equals sign. This will allow you to solve for m in the next few steps:

(cancel2m^(2))/cancel2= 200/2

The 2's cancel out, leaving you with m^(2) equal to 100

m^(2) = 100

In order to get rid of m^(2) to solve for just m, you will need to take the square root on both sides of the equation, since the square root is the inverse of a number that's squared:

sqrtm^(2) = sqrt100

After you square both sides, you are left with m on the left and 10 on the right.

Thus,
color(purple)("m = 10

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