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How do you solve #27^(x+2)=3#?

1 Answer

May 20, 2016

Put in equal bases.

Explanation:

#(3^3)^(x + 2) = 3#

#3^(3x + 6) = 3^1#

#3^(3x) = 3^(1 - 6)#

#3^(3x) = 3^(-5)#

#x = -5/3#

Hopefully this helps!

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