How do you solve $25 x^{2} - 30 x = - 9$ $25x^2-30x=-9$ ?

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Answer 1 · 2016-05-03T21:46:56

$x = \frac{3}{5}$ $x=3/5$

Once you put all of the terms of the quadratic on one side of the equation, then you get a perfect square trinomial:

Add $9$ $9$ to both sides to get:

$0 = 25 x^{2} - 30 x + 9$ $0 = 25x^2-30x+9$

$= {(5 x)}^{2} - 2 (5 x) (3) + 3^{2}$ $=(5x)^2-2(5x)(3)+3^2$

$= {(5 x - 3)}^{2}$ $=(5x-3)^2$

So $x = \frac{3}{5}$ $x = 3/5$

How do you solve 25x^2-30x=-925x2−30x=−925x^2-30x=-9?