How do you solve $25x^2-30x=-9$ ?

Question

5623 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-03T21:46:56

$x=3/5$

Once you put all of the terms of the quadratic on one side of the equation, then you get a perfect square trinomial:

Add $9$ to both sides to get:

$0 = 25x^2-30x+9$

$=(5x)^2-2(5x)(3)+3^2$

$=(5x-3)^2$

So $x = 3/5$

How do you solve 25x^2-30x=-925x^2-30x=-9?