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How do you solve #2^(x-9) = 5 #?

1 Answer

Shwetank Mauria

Aug 12, 2016

#x=11.3223#

Explanation:

As #2^(x-9)=5#, writing in logarithmic form we have

#(x-9)=log_2(5)#, which can be also written as

#(x-9)=log5/log2#

= #0.6990/0.3010=2.3223#

and #x=9+2.3223=11.3223#

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