How do you solve #2(x-5)^2=30#?

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How do you solve #2(x-5)^2=30#?

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Answer 1 · 2015-10-24T05:43:47

#x=+-sqrt(15)+5#
#x~~8.87, 1.13#

Explanation:

First lets divide both sides by #2#,
#(x-5)^2=15#
Now square root both sides,
#x-5=+-sqrt15#
Now take away #5# from both sides,
#x=+-sqrt(15)+5#
Now evaluate:
#x~~8.87, 1.13#

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How do you solve #2(x-5)^2=30#?

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