How do you solve #-2/(x-10)<0#?

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Answer 1 · 2017-09-22T12:17:29

Solution : # x > 10 or (10,oo)#

# - 2/(x-10) < 0 or 2/(x-10) > 0# . Critical point is

#x -10=0 or x=10 ; x != 10 # since for #x=10# , the function

is undefined.

Sign change observation:

When # x <10 # sign of #2/(x-10) # is # - ; i.e <0 #

When # x >10 # sign of #2/(x-10) # is # + ; i.e > 0 #

Solution : # x > 10 or (10,oo)# [Ans]