How do you solve #2( w - 7) - 1= - 3( - 8w + 3) - 7w#?

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Answer 1 · 2017-05-31T19:08:06

#w=10/3# or #w=3 1/3# or #w=3.33bar3#

Step 1. Distribute the #2# and #-3# into the parenthesis.

#color(red)(2)(w-7)-1=color(red)(-3)(-8w+3)-7w#

#2w-14-1=24-9-7w#

Step 2. Add the like terms, #w#s with #w#s and numbers with numbers.

#2w-15=15-7w#

Add #15# to both sides
#2w-15+color(red)(15)=15-7w+color(red)(15)#
#2w=30-7w#

Add #7w# to both sides
#2w+color(red)(7w)=30-7w+color(red)(7w)#
#9w=30#

Divide both sides by #9#
#(cancel(9)w)/(cancel(color(red)(9)))=30/(color(red)(9))#
#w=10/3# or #w=3 1/3# or #w=3.33bar3#