How do you solve $2( w - 7) - 1= - 3( - 8w + 3) - 7w$ ?

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Answer 1 · 2017-05-31T19:08:06

$w=10/3$ or $w=3 1/3$ or $w=3.33bar3$

Step 1. Distribute the $2$ and $-3$ into the parenthesis.

$color(red)(2)(w-7)-1=color(red)(-3)(-8w+3)-7w$

$2w-14-1=24-9-7w$

Step 2. Add the like terms, $w$ s with $w$ s and numbers with numbers.

$2w-15=15-7w$

Add $15$ to both sides
$2w-15+color(red)(15)=15-7w+color(red)(15)$
$2w=30-7w$

Add $7w$ to both sides
$2w+color(red)(7w)=30-7w+color(red)(7w)$
$9w=30$

Divide both sides by $9$
$(cancel(9)w)/(cancel(color(red)(9)))=30/(color(red)(9))$
$w=10/3$ or $w=3 1/3$ or $w=3.33bar3$

How do you solve 2( w - 7) - 1= - 3( - 8w + 3) - 7w2( w - 7) - 1= - 3( - 8w + 3) - 7w?