How do you solve $2 (w - 7) - 1 = - 3 (- 8 w + 3) - 7 w$ $2( w - 7) - 1= - 3( - 8w + 3) - 7w$ ?

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Answer 1 · 2017-05-31T19:08:06

$w = \frac{10}{3}$ $w=10/3$ or $w = 3 \frac{1}{3}$ $w=3 1/3$ or $w = 3.33 ¯ 3$ $w=3.33bar3$

Step 1. Distribute the $2$ $2$ and $- 3$ $-3$ into the parenthesis.

$2 (w - 7) - 1 = - 3 (- 8 w + 3) - 7 w$ $color(red)(2)(w-7)-1=color(red)(-3)(-8w+3)-7w$

$2 w - 14 - 1 = 24 - 9 - 7 w$ $2w-14-1=24-9-7w$

Step 2. Add the like terms, $w$ $w$ s with $w$ $w$ s and numbers with numbers.

$2 w - 15 = 15 - 7 w$ $2w-15=15-7w$

Add $15$ $15$ to both sides
$2 w - 15 + 15 = 15 - 7 w + 15$ $2w-15+color(red)(15)=15-7w+color(red)(15)$
$2 w = 30 - 7 w$ $2w=30-7w$

Add $7 w$ $7w$ to both sides
$2 w + 7 w = 30 - 7 w + 7 w$ $2w+color(red)(7w)=30-7w+color(red)(7w)$
$9 w = 30$ $9w=30$

Divide both sides by $9$ $9$
$(cancel(9)w)/(cancel(color(red)(9)))=30/(color(red)(9))$
$w=10/3$ or $w=3 1/3$ or $w=3.33bar3$

How do you solve 2( w - 7) - 1= - 3( - 8w + 3) - 7w2(w−7)−1=−3(−8w+3)−7w2( w - 7) - 1= - 3( - 8w + 3) - 7w?