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How do you solve #2 cos^2 ø - cos ø = 0#?

1 Answer

Apr 19, 2016

#S={pi/2 +pin, +-pi/3 +2pin}#

Explanation:

#cos phi(2cos phi-1)=0#

#cos phi =0, 2 cos phi-1=0#

#cos phi=0 or cos phi =1/2#

#phi=cos^-1 0 or phi=cos^-1 (1/2)#

#phi=pi/2 +pin, +-pi/3 +2pin#

#S={pi/2 +pin, +-pi/3 +2pin}#

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