How do you solve $\frac{2}{3} y - 6 = 12$ $2/3y-6=12$ ?

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How do you solve $\frac{2}{3} y - 6 = 12$ $2/3y-6=12$ ?

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Answer 1 · 2016-10-27T14:53:41

$y = 27$ $y = 27$

Explanation:

First add $6$ $6$ to each side to give:

$(\frac{2}{3}) y = 18$ $(2/3)y = 18$

Then multiple each side by $\frac{3}{2}$ $3/2$ to give:

$y = 27$ $y = 27$

Answer 2 · 2016-10-27T14:59:49

Work backwards to isolate y ( PE SADM)

Explanation:

Do parenthesis and then use the order of operations backwards.

SA comes first so do the subtraction and addition first. The opposite of of -6 is + 6 so add 6 to both sides.

$\frac{2}{3} \times y - 6 + 6 = 12 + 6$ $2/3xx y - 6 + 6 = 12 + 6$ This results in

$\frac{2}{3} \times y = 18$ $2/3 xx y = 18$

Next comes DM so divide and multiply by the opposite.

The opposite or inverse of $\frac{2}{3}$ $2/3$ is $\frac{3}{2}$ $3/2$ so multiply both sides by $\frac{3}{2}$ $3/2$

$\frac{2}{3} \times \frac{3}{2} \times y = 18 \times \frac{3}{2}$ $2/3 xx 3/2 xx y = 18 xx 3/2$ : $\frac{2}{3} \times \frac{3}{2} = 1$ $2/3 xx 3/2 = 1$ so

y  =  27

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