How do you solve $\frac{2}{3} x + 11 = 7$ $2/3x+11=7$ ?

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Answer 1 · 2015-06-29T08:42:01

$x = - 6$ $color(green)(x =-6$

$(\frac{2}{3}) x + 11 = 7$ $(2/3) x +11 =7$

$\frac{2 x + 33}{3} = 7$ $(2x +33) / 3 =7$

$(2 x + 33) = 21$ $(2x +33) =21$

$2 x = - 12$ $2x =-12$
$x = - 6$ $color(green)(x =-6$

How do you solve 23x+11=72/3x+11=7?