How do you solve $\frac{2}{3} n - 7 = 19$ $2/3n - 7 = 19$ ?

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Answer 1 · 2015-08-05T13:47:46

$n = 39$ $color(blue)(n=39$

$\frac{2}{3} n - 7 = 19$ $2/3n−7=19$

$\frac{2 n - 21}{3} = 19$ $(2n−21)/3=19$

$2 n - 21 = 19 \cdot 3$ $2n−21=19*3$

$2 n = 57 + 21$ $2n=57 +21$

$2 n = 78$ $2n=78$

$n = \frac{78}{2}$ $n=78/2$

$n = 39$ $color(blue)(n=39$

Answer 2 · 2015-08-05T13:50:05

You isolate $n$ $n$ on one side of the equation to get $n = 39$ $n=39$ .

All you need to do in order to solve this equation is get $n$ $n$ alone on one side of the equation.

To do that, start by adding $7$ $7$ to both sides of the equation

$2/3n - color(red)(cancel(color(black)(7))) + color(red)(cancel(color(black)(7))) = 19 + 7$

$2/3n = 26$

Now multiply boh sides of the equation by $3/2$ to get

$color(red)(cancel(color(black)(3/2))) * color(red)(cancel(color(black)(2/3))) n = 26 * 3/2$

$n = color(green)(39)$

How do you solve 2/3n - 7 = 1923n−7=192/3n - 7 = 19?