How do you solve $2^(3-x) = 565$ ?

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Answer 1 · 2016-07-21T14:29:23

$x=3-(log 565)/(log 2)=-6.142107057$

We start from the given equation

$2^(3-x)=565$

Take the logarithm of both sides

$log 2^(3-x)=log 565$

$(3-x)*log 2=log 565$

$3-x=log 565/log 2$

$3-log 565/log 2=x$

and

$x=3-(log 565)/(log 2)=-6.142107057$

God bless....I hope the explanation is useful

How do you solve 2^(3-x) = 5652^(3-x) = 565?