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How do you solve #2/3(a-3)=1/3#?

1 Answer

Jun 13, 2015

#a = 7/2#

Explanation:

First we need to "delete" #2/3# by multiplying both side by the inverse of #2/3 => (2/3)^-1=3/2#

#=>a-3=1/2#

and then add #3# both side

#=>a = 1/2 + 3 = 7/2#

Finally we have

#a = 7/2#

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