How do you solve #-18- 6k = 6( 1+ 3k )#?
1 Answer
Oct 3, 2017
Explanation:
#"distribute the bracket on the right side"#
#-18-6k=6+18k#
#"collect terms in k on the left side and numeric values"#
#"on the right side"#
#"subtract 18k from both sides"#
#-18-6k-18k=6cancel(+18k)cancel(-18k)#
#rArr-18-24k=6#
#"add 18 to both sides"#
#cancel(-18)cancel(+18)-24k=6+18#
#rArr-24k=24#
#"divide both sides by "-24#
#(cancel(-24) k)/cancel(-24)=24/(-24)#
#rArrk=-1#
#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.
#"left "=-18+6=-12#
#"right "=6(1-3)=6xx-2=-12#
#rArrk=-1" is the solution"#
