How do you solve #15x^2 + 7x=2#?

1 Answer
Nghi N.
May 26, 2015

y = 15x^2 + 7x - 2 = 0.(1). I use the new Transformation Method for solving quadratic equations. (Google, Yahoo Search)
Transformed equation: x^2 + 7x - 30 = 0 (2)
Factor pairs of a.c = -30 --> (-2, 15)(-3, 10). This sum is 10 -3 = 7 = b.
Then 2 real roots of (2) are: 3 and -10.
Back to (1), the 2 real roots are: #3/15 = 1/5# and #-10/15 = -2/3#.

This Transformation Method is fast, systematic, no factoring by grouping, no solving binomials.

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