How do you solve $- 12 x^{2} + 5 x + 2 = 0$ $-12x^2 + 5x +2=0$ using the quadratic formula?

Question

4610 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-16T10:09:52

$x_{1} = - \frac{1}{4}$ $x_1=-1/4" "$ and $x_{2} = \frac{2}{3}$ $x_2=2/3$

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x=(-b+-sqrt(b^2-4ac))/(2a)$

Let $a = - 12$ $a=-12$ and $b = 5$ $b=5$ and $c = 2$ $c=2$

$y = \frac{- 5 \pm \sqrt{{(5)}^{2} - 4 \cdot (- 12) \cdot (2)}}{2 (- 12)}$ $y=(-5+-sqrt((5)^2-4*(-12)*(2)))/(2(-12))$

$y = \frac{- 5 \pm \sqrt{25 + 96}}{- 24}$ $y=(-5+-sqrt(25+96))/(-24)$

$y = \frac{- 5 \pm \sqrt{121}}{- 24}$ $y=(-5+-sqrt(121))/(-24)$

$y_{1} = \frac{- 5 + 11}{- 24} = \frac{6}{- 24} = - \frac{1}{4}$ $y_1=(-5+11)/(-24)=6/-24=-1/4$

$y_{2} = \frac{- 5 - 11}{- 24} = - \frac{16}{- 24} = \frac{2}{3}$ $y_2=(-5-11)/(-24)=-16/(-24)=2/3$

God bless.... I hope the explanation is useful.

How do you solve -12x^2 + 5x +2=0−12x2+5x+2=0-12x^2 + 5x +2=0 using the quadratic formula?