How do you solve $12x^2-15x= 0$ using the quadratic formula?

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Answer 1 · 2016-06-19T14:14:14

$x=0 and x=5/4$

Before you apply the quadratic formula, consider

a=12
b=-15
c=0

so, by substituting in the formula

$x=(-b+-sqrt(b^2-4ac))/(2a)$ ,

you find

$x=(15+-sqrt(225-4*12*0))/(2*12)$

$x=(15+-15)/24$

$x=0 and x=30/24=5/4$

How do you solve 12x^2-15x= 012x^2-15x= 0 using the quadratic formula?