How do you solve 10x^2 - 19x + 6 = 0 using the quadratic formula?

1 Answer
Shantelle
Aug 4, 2018

x = (19 + 2sqrt19)/20 and x = (19 - 2sqrt19)/20

Explanation:

10x^2 - 19x + 6 = 0

The quadratic formula is x = (-b +- sqrt(b^2 - 4ac))/(2a).

We know that: a = 10, b = -19, and c = 6 based on the equation, so let's plug them into the formula:
x = (-(-19) +- sqrt((-19)^2 - 4(10)(6)))/(2(10))

x = (19 +- sqrt(361 - 240))/20

x = (19 +- sqrt76)/20

x = (19 +- sqrt(4*19))/20

x = (19 +- 2sqrt19)/20

Hope this helps!

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