How do you solve $(10h)/108=5/9$ ?

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Answer 1 · 2016-12-26T19:05:21

$10/108h=5/9$

Multiply each side by the reciprocal of the coefficient of h. The coefficient of h is $10/108$ , so the reciprocal is $108/10$

$h=(5/9)*(108/10)$

$h=(1/1)*(12/2)$

$h=6$

Answer 2 · 2016-12-26T19:11:47

$h = 6$

$(10h)/108 = 5/9" "larr$ isolate $h$ by $xx 108/10$ on both sides

$108/10 xx(10h)/108 = 108/10xx5/9$

$h= cancel108^12/cancel10^2xxcancel5/cancel9$

$h = 6$

Notice that cancelling first avoids ending up with

$h = 540/90$

How do you solve (10h)/108=5/9(10h)/108=5/9?