How do you solve $10(x-7)^2=440$ ?

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Answer 1 · 2018-03-02T02:53:39

$x = 7-2sqrt(11), 7+2sqrt(11)$

Divide both sides by 10:

$(x-7)^2=44$

Take the square root of both sides

$x-7=+-sqrt(44)$

Add seven to both sides

$x=7+-sqrt(44)$

You can simplify the square root. A perfect square of $4$ goes in there, so

$x=7+-2sqrt(11)$

Answer = $7-2sqrt(11), 7+2sqrt(11)$

How do you solve 10(x-7)^2=44010(x-7)^2=440?