How do you solve $- \frac{10}{x - 5} \geq - \frac{11}{x - 6}$ $-10/(x-5)>=-11/(x-6)$ ?

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How do you solve $- \frac{10}{x - 5} \geq - \frac{11}{x - 6}$ $-10/(x-5)>=-11/(x-6)$ ?

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Answer 1 · 2016-10-02T02:55:18

Get rid of the fractions and divide everything by a negative including the $\geq$ $>=$ sign.

Explanation:

Multiply both sides by (x-5)(x-6) This will get rid of the fractions.

$(x - 5) (x - 6) \times - \frac{10}{x - 5} \geq (x - 5) (x - 6) \times - \frac{11}{x - 6}$ $(x-5)(x-6)xx -10/(x-5) >= (x-5)(x-6) xx -11/(x-6)$ This gives

$(x - 6) \times - 10 \geq (x - 5) \times - 11$ $(x-6) xx -10 >= (x-5) xx -11$ multiplying across the ( ) gives

$- 10 x + 60 \geq - 11 x + 55$ $- 10x + 60 >= -11 x + 55$ adding + 10x to both sides gives

$- 10 x + 10 x + 60 \geq - 11 x + 10 x + 55$ $-10x + 10 x + 60 >= - 11x + 10 x + 55$ resulting in

$+ 60 \geq - 1 x + 55$ $+ 60 >= -1 x + 55$ subtract 55 from both sides

$+ 60 - 55 \geq - 1 x + 55 - 55$ $+ 60 - 55 >= -1 x + 55 -55$ +5 resulting in

$+ 5 \geq - 1 x$ $+ 5 >= -1 x$ Now divide everything by -1

$+ \frac{5}{- 1} \frac{\geq}{- 1} (- 1 \frac{x}{- 1})$ $+ 5/-1 >=/-1 (-1x/-1)$

$+ \frac{5}{- 1}$ $+5/-1$ = -5 the opposite of +5

$\frac{\geq}{- 1}$ $>=/-1$ = $\leq$ $<=$ The opposite of $\geq$ $>=$

$- 1 \frac{x}{- 1}$ $-1 x/-1$ = + 1 x The opposite of -1 x so the answer is

$x \geq - 5$ $x >= -5$

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How do you solve $- \frac{10}{x - 5} \geq - \frac{11}{x - 6}$ $-10/(x-5)>=-11/(x-6)$ ?

1 Answer

Explanation:

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How do you solve −10x−5≥−11x−6-10/(x-5)>=-11/(x-6)?

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How do you solve $- \frac{10}{x - 5} \geq - \frac{11}{x - 6}$ $-10/(x-5)>=-11/(x-6)$ ?