How do you solve -10-5n^2=-330?

2 Answers
smendyka
Jun 12, 2017

See a solution process below:

Explanation:

First, add color(red)(10) to each side of the equation to isolate the n term while keeping the equation balanced:

color(red)(10) - 10 - 5n^2 = color(red)(10) - 330

0 - 5n^2 = -320

-5n^2 = -320

Next, divide each side of the equation by color(red)(-5) to isolate x^2 while keeping the equation balanced:

(-5n^2)/color(red)(-5) = (-320)/color(red)(-5)

(color(red)(cancel(color(black)(-5)))n^2)/cancel(color(red)(-5)) = 64

n^2 = 64

Now, take the square root of each side of the equation to solve for n while keeping the equation balanced. Remember, the square root of a number produces a positive and negative result:

sqrt(n^2) = +-sqrt(64)

n = +-8

Cri007
Jun 13, 2017

See below

Explanation:

-10-5n^2=-330

320=5n^2

64=n^2

n=pm8

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