How do you solve $1 + sin (x) = cos (x)$ $1 + sin(x) = cos(x)$ ?

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How do you solve $1 + sin (x) = cos (x)$ $1 + sin(x) = cos(x)$ ?

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Answer 1 · 2016-09-06T11:41:48

$x = 0$ $x=0$

Explanation:

$1 + sin (x) = cos (x) or cos x - sin x = 1$ $1+sin(x)=cos(x) or cosx-sinx=1$ . Squaring both sides we get ${(cos x - sin x)}^{2} = 1 or {cos}^{2} x + {sin}^{2} x - 2 sin x cos x = 1 or 1 - sin 2 x = 1 or sin 2 x = 0 = sin 0;$ $(cosx-sinx)^2=1 or cos^2x+sin^2x -2sinxcosx=1 or 1-sin2x=1 or sin2x=0=sin0;$ We know $sin0=0:.2x=0 or x=0$ [Ans]

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How do you solve $1 + sin (x) = cos (x)$ $1 + sin(x) = cos(x)$ ?

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How do you solve $1 + sin (x) = cos (x)$ $1 + sin(x) = cos(x)$ ?