How do you solve 1-cot^2x=0 and find all solutions in the interval 0<=x<360?

1 Answer
Bdub
Oct 3, 2016

S={pi/4,(3pi)/4, (5pi)/4, (7pi)/4 }

Explanation:

1-cot^2x=0
cot^2x=1
cotx=+- sqrt 1
x=cot^-1 (+-1)
x=pi/4 +pin, x= -pi/4 +pin
n=0, x= pi/4, -pi/4
n=1, x=(3pi)/4, (5pi)/4
n=2, x= (7pi)/4, (9pi)/4
S={pi/4,(3pi)/4, (5pi)/4, (7pi)/4 }

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