How do you solve #1-cot^2x=0# and find all solutions in the interval #0<=x<360#?

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How do you solve #1-cot^2x=0# and find all solutions in the interval #0<=x<360#?

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Answer 1 · 2016-10-03T17:46:16

#S={pi/4,(3pi)/4, (5pi)/4, (7pi)/4 }#

Explanation:

#1-cot^2x=0#
#cot^2x=1#
#cotx=+- sqrt 1#
#x=cot^-1 (+-1)#
#x=pi/4 +pin, x= -pi/4 +pin#
#n=0, x= pi/4, -pi/4#
#n=1, x=(3pi)/4, (5pi)/4#
#n=2, x= (7pi)/4, (9pi)/4#
#S={pi/4,(3pi)/4, (5pi)/4, (7pi)/4 }#

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How do you solve #1-cot^2x=0# and find all solutions in the interval #0<=x<360#?

1 Answer

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