How do you solve #1/(cosx-sinx)=cosx+sinx#?
1 Answer
Dec 7, 2016
Explanation:
Make the equation into a product.
#1 = (cosx + sinx)(cosx - sinx)#
#1 = cos^2x - sin^2x#
Solve the pythagorean identity
#1 = 1- sin^2x - sin^2x#
#0 = -2sin^2x#
#0 = sinx#
#x = 0 + 2pin, pi + 2pin#
Our restrictions are
Hopefully this helps!
