How do you solve $0 = x^2 - 5/2x + 1/2$ using the quadratic formula?

Question

1915 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-05T09:57:15

$x^2-2.5x+0.5=0$ and $x1=2.28$ and $x2=0.219$

Let me calculate delta first: $Delta=b^2-(4*a*c)$ where a is 1 b is -2.5 and c is 0.5. Then $Delta=4.25$ .

Using solution $x1=(-b+sqrt(Delta))/(2a)$ and $x2=(-b-sqrt(Delta))/(2a)$
you can get $x1=2.28$ and $x2=0.219$

How do you solve 0 = x^2 - 5/2x + 1/20 = x^2 - 5/2x + 1/2 using the quadratic formula?