How do you solve #-0.6y-9.3=1.206#?

Question

1049 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-20T20:01:02

See entire solution process below;

First step, add #color(red)(9.3)# to each side of the equation to isolate the #y# term while keeping the equation balanced:

#-0.6y - 9.3 +color(red)(9.3) = 1.206 + color(red)(9.3)#

#-0.6y - 0 = 10.506#

#-0.6y = 10.506#

Next, divide each side of the equation by #color(red)(-0.6)# to solve for #y# while keeping the equation balanced:

#(-0.6y)/color(red)(-0.6) = 10.506/color(red)(-0.6)#

#(color(red)(cancel(color(black)(-0.6)))y)/cancel(color(red)(-0.6)) = -17.51#

#y = -17.51#