How do you solve #0=1/2x-3#?

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Answer 1 · 2017-04-21T03:33:09

See the entire solution process below:

First, add #color(red)(3)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#0 + color(red)(3) = 1/2x - 3 + color(red)(3)#

#3 = 1/2x - 0#

#3 = 1/2x#

Now, multiply each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#color(red)(2) * 3 = color(red)(2) * 1/2x#

#6 = cancel(color(red)(2)) * 1/color(red)(cancel(color(red)(2)))x#

#6 = 1x#

#1x = 6#

#x = 6#