How do you simplity #6cot2theta-costheta# to trigonometric functions of #theta#? Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Ratnaker Mehta Jul 6, 2016 #3(cottheta-tantheta)-costheta.# Explanation: #cot2theta=cos(2theta)/sin(2theta)=(cos^2theta-sin^2theta)/(2sinthetacostheta)=1/2{cos^2theta/(costhetasintheta)-sin^2theta/(sinthetacostheta)}=1/2(cottheta-tantheta)# Hence, the Given Exp. #=3(cottheta-tantheta)-costheta.# Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for #sin 2x = cos x# for the interval #[0,2pi]#? How do you find all solutions for #4sinthetacostheta=sqrt(3)# for the interval #[0,2pi]#? How do you simplify #cosx(2sinx + cosx)-sin^2x#? If #tan x = 0.3#, then how do you find tan 2x? If #sin x= 5/3#, what is the sin 2x equal to? How do you prove #cos2A = 2cos^2 A - 1#? See all questions in Double Angle Identities Impact of this question 1322 views around the world You can reuse this answer Creative Commons License